![]() Hence the variable in the code above should be, var dynamicPart = "\\s*XYZ" But the above code will return false as output, because when the RegExp object will get created it will have s* in the pattern rather than \s*, hence we must escape the backslash with another backslash. We have also changed in the input variable to (added a space). If you look closely in the code above, we have added a \s* tin the dynamicPart variable, which is to match spaces, newlines, etc. Yes, to escape any special character in regular expression string, we add a backslash in front of it. But if the dynamic part or the value of the variable which will be added dynamically has a \ (backslash) which has meaning in regular expression pattern, then we should escape this by adding another backslash. We do not have to escape most of the characters, like we can see in the example above, the code works perfectly. Using RegExp object's constructor functionĮscaping Characters in Regular Expression Pattern: There are two different ways of using a regular expression in JavaScript, they are: We can use regex to perform any type of text search and text replace operations. When we search for some specific data in a text, we can use a regular expression to be used as a search pattern to describe what you are searching for.Ī regular expression can be a single character or a more complicated pattern. In JavaScript, Regular Expressions also known as regex are patterns used to match, replace, compare character combinations in strings. ![]() In the above code example, we are matching a custom HTML tag, and the above script can be used to match any HTML tag, but just replacing the value for the dynamicPart variable, because that will automatically update the regular expression pattern. ![]() the line above is same as, var regex = /\074abc\076/ Var regexObj = new RegExp("\074" dynamicPart "\076") // will match Here is the solution for you: var dynamicPart = "XYZ" We can use the JavaScript RegExp Object for creating a regex pattern from a dynamic string. But how do we use dynamic (variable) string as a regex pattern in JavaScript? To make a regular expression dynamic, we can use a variable to change the regular expression pattern string by changing the value of the variable. ![]()
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